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9n^2+60n-21=0
a = 9; b = 60; c = -21;
Δ = b2-4ac
Δ = 602-4·9·(-21)
Δ = 4356
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4356}=66$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-66}{2*9}=\frac{-126}{18} =-7 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+66}{2*9}=\frac{6}{18} =1/3 $
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